12u^2-25u=+12

Solution for 12u^2-25u=+12 equation:

12u^2-25u=+12

We move all terms to the left:

12u^2-25u-(+12)=0

We add all the numbers together, and all the variables

12u^2-25u-12=0

a = 12; b = -25; c = -12;
Δ = b2-4ac
Δ = -252-4·12·(-12)
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{1201}}{2*12}=\frac{25-\sqrt{1201}}{24}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{1201}}{2*12}=\frac{25+\sqrt{1201}}{24}
$